type 7 finding sum difference product based ratio & proportion problems Practice Questions Answers Test with Solutions & More Shortcuts
ratio & proportion PRACTICE TEST [9 - EXERCISES]
type 1 basic concepts of ratio & proportion
type 2 age based ratio & proportion problems
type 3 addition subtraction product on ratio & proportion
type 4 income & expenditure based ratio & proportion problems
type 5 shares & partnership based ratio & proportion problems
type 6 fractions based ratio & proportion problems
type 7 finding sum difference product based ratio & proportion problems
type 8 alligation & mixtures based ratio & proportion problems
type 9 coins & rupees based ratio & proportion problems
Question : 16 [SSC CHSL 2012]
The total number of students in a school was 660. The ratio between boys and girls was 13 : 9. After some days, 30 girls joined the school and some boys left the school and new ratio between boys and girls became 6 : 5. The number of boys who left the school is :
a) 30
b) 60
c) 40
d) 50
Answer »Answer: (a)
In the first case,
Boys = $660 × 13/22$ = 390
Girls = $660 × 9/22$ = 270
If x boys leave the school, then
${390 - x}/{270 + 30} = 6/5$
390 - x = 360
x = 390 - 360 = 30
Question : 17 [SSC CPO S.I.2006]
The ratio of the number of ladies to that of gents at a party was 3 : 2. When 20 more gents joined the party, the ratio was reversed. The number of ladies present at the party was
a) 24
b) 16
c) 32
d) 36
Answer »Answer: (a)
Let the number of ladies and gents be 3x and 2x respectively.
According to the question,
${3x}/{2x + 20} = 2/3$
9x = 4x + 40
5x = 40 ⇒ x = 8
Number of ladies = 3x
= 3 × 8 = 24
Question : 18 [SSC CGL Tier-I 2013]
Three numbers are in the ratio 1 : 2 : 3. By adding 5 to each of them, the new numbers are in the ratio 2 : 3 : 4. The numbers are:
a) 1, 2, 3
b) 5, 10, 15
c) 15, 30, 45
d) 10, 20, 30
Answer »Answer: (b)
Numbers = x, 2x and 3x
${x + 5}/{2x + 5}= 2/3$
4x + 10 = 3x + 15
x = 5
Numbers = 5, 10 and 15
Question : 19 [SSC CGL Prelim 2002]
The students in three classes are in the ratio 2 : 3 : 5. If 40 students are increased in each class, the ratio changes to 4 : 5 : 7. Originally, the total number of students was :
a) 200
b) 400
c) 180
d) 100
Answer »Answer: (a)
Let the number of students in three classes be 2x, 3x and 5x respectively.
Due to increase of 40 students in each class,
we have ${2x + 40}/{3x + 40} = 4/5$
10x + 200 = 12x + 160
2x = 200 - 160
2x = 40 ⇒ x = 20
Original strength
= 10x = 10 × 20 = 200
Question : 20 [SSC CGL Tier-I 2010]
What must be added to each term of the ratio 7 : 11, so as to make it equal to 3 : 4 ?
a) 6.5
b) 5
c) 7.5
d) 8
Answer »Answer: (b)
Let the required number be x.
${7 + x}/{11 + x} = 3/4$
28 + 4x = 33 + 3x
x = 33 - 28 = 5
IMPORTANT quantitative aptitude EXERCISES
-
199+ Ratio Proportion Basic Concepts MCQ Questions Answers »
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Top 199+ Ratio Proportion Age Based MCQ Questions Answers »
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159+ Ratios Proportions Addition Subtraction product MCQ »
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199+ Ratio Proportion Income, Expenditure Problems MCQS »
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199+ Partnership Aptitude (Ratio) MCQ Questions Answers »
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259+ Ratio and Proportion (fractions) Aptitude MCQ Quiz »
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199+ Ratio and Proportion Aptitude Questions Answers MCQ »
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299+ Alligation and Mixture Problems Aptitude MCQ Quiz »
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249+ Ratio and Proportion Coins Based Questions Answers »
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